I have a list whose size is a multiple of 16. What I want to do is go through the list and get 16 elements and create a list from those values, and then store those values somewhere. After that I can either ignore them or remove them from the list, and continue this process until the bigger list is empty. What I was trying to do was to go through the list, and keep a counter of some sort to keep track of the number of elements that have been appended to the list. However, I have been stuck from there. Any ideas on how to accomplish on what I am trying to do? Any ideas would be greatly appreciated.
lst = [[1, 4, 0], [2, 4, 0], [3, 4, 0], [4, 4, 0], [1, 3, 0], [2, 3, 0], [3, 3, 0], [4, 3, 0], [1, 2, 0], [2, 2, 0], [3, 2, 0], [4, 2, 0], [1, 1, 0], [2, 1, 0], [3, 1, 0], [4, 1, 0],[1, 4, 0], [2, 4, 0], [3, 4, 0], [4, 4, 0], [1, 3, 0], [2, 3, 0], [3, 3, 0], [4, 3, 0], [1, 2, 0], [2, 2, 0], [3, 2, 0], [4, 2, 0], [1, 1, 0], [2, 1, 0], [3, 1, 0], [4, 1, 0]]
If I understand you correctly, you start with a list of size n, where n % 16 == 0. You want to end with n/16 lists of size 16. You can accomplish this pretty easily with a double for loop. The outer loop should go for n/16 iterations. the inner loop should go for 16 iterations. The outer loop creates a new list with each iteration. the inner loop takes elements from the original list and appends them to the newly created list.
Thank you for taking the time to respond to my question. After clicking on random links on the right hand side I came to answer that did exactly what I needed to happen. Here is the solution to my problem:
[input[i:i+n] for i in range(0, len(input), n)]
The solution above goes through input and creates a list of size n.
I have a list whose size is a multiple of 16. What I want to do is go through the list and get 16 elements and create a list from those values, and then store those values somewhere. After that I can either ignore them or remove them from the list, and continue this process until the bigger list is empty. What I was trying to do was to go through the list, and keep a counter of some sort to keep track of the number of elements that have been appended to the list. However, I have been stuck from there. Any ideas on how to accomplish on what I am trying to do? Any ideas would be greatly appreciated.
lst = [[1, 4, 0], [2, 4, 0], [3, 4, 0], [4, 4, 0], [1, 3, 0], [2, 3, 0], [3, 3, 0], [4, 3, 0], [1, 2, 0], [2, 2, 0], [3, 2, 0], [4, 2, 0], [1, 1, 0], [2, 1, 0], [3, 1, 0], [4, 1, 0],[1, 4, 0], [2, 4, 0], [3, 4, 0], [4, 4, 0], [1, 3, 0], [2, 3, 0], [3, 3, 0], [4, 3, 0], [1, 2, 0], [2, 2, 0], [3, 2, 0], [4, 2, 0], [1, 1, 0], [2, 1, 0], [3, 1, 0], [4, 1, 0]]
If I understand you correctly, you start with a list of size n, where n % 16 == 0. You want to end with n/16 lists of size 16. You can accomplish this pretty easily with a double for loop. The outer loop should go for n/16 iterations. the inner loop should go for 16 iterations. The outer loop creates a new list with each iteration. the inner loop takes elements from the original list and appends them to the newly created list.
Thank you for taking the time to respond to my question. After clicking on random links on the right hand side I came to answer that did exactly what I needed to happen. Here is the solution to my problem:
[input[i:i+n] for i in range(0, len(input), n)]
The solution above goes through input and creates a list of size n.
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