python - Django fonctionnalité de page dynamique et url - Stack Overflow

I have a some problem with routing in my django app.

The problem: There is some dynamic website and site administrator can create pages with random urls. For example, he can create a news page with url "company/news" or "store/news". Or he can create the page with feedback form with url "feedback" or "user/feedback".

So, Django needs to catch this request and show appropriate news or feedback content for these pages. How can I route the user request to the appropriate view according to the requested page functionality?

You can create view that parses your URL and chooses strategy for different types.

# urls.py
...
url(r'^dynamic-view/(?P<dynamic_view_url>.*)/$', 'dynamic_view')


# views.py
def dynamic_view(request, dynamic_view_url):
    url_parts = [p for p in dynamic_view_url.split("/") if p]
    if "feedback" in url_parts:
        return _view_for_feedback(request, url_parts)
    elif "news" in url_parts:
        return _view_for_news(request, url_parts)
    else:
        raise Http404

I have a some problem with routing in my django app.

The problem: There is some dynamic website and site administrator can create pages with random urls. For example, he can create a news page with url "company/news" or "store/news". Or he can create the page with feedback form with url "feedback" or "user/feedback".

So, Django needs to catch this request and show appropriate news or feedback content for these pages. How can I route the user request to the appropriate view according to the requested page functionality?

You can create view that parses your URL and chooses strategy for different types.

# urls.py
...
url(r'^dynamic-view/(?P<dynamic_view_url>.*)/$', 'dynamic_view')


# views.py
def dynamic_view(request, dynamic_view_url):
    url_parts = [p for p in dynamic_view_url.split("/") if p]
    if "feedback" in url_parts:
        return _view_for_feedback(request, url_parts)
    elif "news" in url_parts:
        return _view_for_news(request, url_parts)
    else:
        raise Http404

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