informations de trouver la Version de système d'exploitation Windows - écriture de scripts Batch - - sortie Variable - Stack Overflow

I have a script that works perfectly.

 if not exist %SystemRoot%\system32\systeminfo.exe goto warnthenexit

 systeminfo | find "OS Name" > osname.txt

 FOR /F "usebackq delims=: tokens=2" %%i IN (osname.txt) DO set vers=%%i

 echo %vers% | find "Windows 7" > nul

 if %ERRORLEVEL% == 0 goto VERSION_7

However, when I try to print the results like so:

Echo Current OS:%vers% - 64 Bit

It prints the results with a really! long gap. Like so:

Current OS:                   Microsoft Windows 7 Enterprise  - 64 Bit

Does anyone know why? or how I can remove the large gap?

Thanks a million!

Changed

FOR /F "usebackq delims=: tokens=2" %%i IN (osname.txt) DO set vers=%%i

To

FOR /F "usebackq delims=  tokens=2" %%i IN (osname.txt) DO set vers=%%i

*Changed the : to a %space% after delims...

I know your script "works perfectly", but is not much efficient.

SYSTEMINFO takes a lot of time and osname.txt may be avoided.

Check:

FOR /F "TOKENS=1,* DELIMS==" %%u IN ('WMIC OS GET CAPTION /VALUE') DO IF /I "%%u"=="Caption" SET vers=%%v

OK, so this used to work, but all of a sudden stopped working ... Any ideas why?

@echo off

:Windows Version Check
if not exist %SystemRoot%\system32\systeminfo.exe goto warnthenexit
systeminfo | find "OS Name" > %TEMP%\osname.txt
FOR /F "usebackq delims=   tokens=2" %%i IN (%TEMP%\osname.txt) DO set vers=%%i

echo %vers% | find "Windows 7" > nul
if %ERRORLEVEL% == 0 goto VERSION_7

echo %vers% | find "Windows Vista" > nul
if %ERRORLEVEL% == 0 goto VERSION_VISTA

ver | find "XP" > nul
if %ERRORLEVEL% == 0 goto VERSION_XP


:VERSION_7
Set RegQry=HKLM\Hardware\Description\System\CentralProcessor\0
REG.exe Query %RegQry% > checkOS.txt
Find /i "x86" < CheckOS.txt > StringCheck.txt
If %ERRORLEVEL% == 0 (
    @Echo         Current OS: %vers% - 32 Bit
) ELSE (
    @Echo         Current OS: %vers% - 64 Bit
)

I have a script that works perfectly.

 if not exist %SystemRoot%\system32\systeminfo.exe goto warnthenexit

 systeminfo | find "OS Name" > osname.txt

 FOR /F "usebackq delims=: tokens=2" %%i IN (osname.txt) DO set vers=%%i

 echo %vers% | find "Windows 7" > nul

 if %ERRORLEVEL% == 0 goto VERSION_7

However, when I try to print the results like so:

Echo Current OS:%vers% - 64 Bit

It prints the results with a really! long gap. Like so:

Current OS:                   Microsoft Windows 7 Enterprise  - 64 Bit

Does anyone know why? or how I can remove the large gap?

Thanks a million!

Changed

FOR /F "usebackq delims=: tokens=2" %%i IN (osname.txt) DO set vers=%%i

To

FOR /F "usebackq delims=  tokens=2" %%i IN (osname.txt) DO set vers=%%i

*Changed the : to a %space% after delims...

I know your script "works perfectly", but is not much efficient.

SYSTEMINFO takes a lot of time and osname.txt may be avoided.

Check:

FOR /F "TOKENS=1,* DELIMS==" %%u IN ('WMIC OS GET CAPTION /VALUE') DO IF /I "%%u"=="Caption" SET vers=%%v

OK, so this used to work, but all of a sudden stopped working ... Any ideas why?

@echo off

:Windows Version Check
if not exist %SystemRoot%\system32\systeminfo.exe goto warnthenexit
systeminfo | find "OS Name" > %TEMP%\osname.txt
FOR /F "usebackq delims=   tokens=2" %%i IN (%TEMP%\osname.txt) DO set vers=%%i

echo %vers% | find "Windows 7" > nul
if %ERRORLEVEL% == 0 goto VERSION_7

echo %vers% | find "Windows Vista" > nul
if %ERRORLEVEL% == 0 goto VERSION_VISTA

ver | find "XP" > nul
if %ERRORLEVEL% == 0 goto VERSION_XP


:VERSION_7
Set RegQry=HKLM\Hardware\Description\System\CentralProcessor\0
REG.exe Query %RegQry% > checkOS.txt
Find /i "x86" < CheckOS.txt > StringCheck.txt
If %ERRORLEVEL% == 0 (
    @Echo         Current OS: %vers% - 32 Bit
) ELSE (
    @Echo         Current OS: %vers% - 64 Bit
)

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