Courriel - bug dans mon mail envoyer pogram en python - Stack Overflow ~ Stackoverflow Blog

I am trying to create a mail sending script using smtp server and python. I am using csv to store the addresses, and then the script use them to create sending request using email lib.

for f, t in zip(FROM,TO):
    s = smtplib.SMTP('localhost')
    msg['From']= f
    msg['To'] = t  
    s.sendmail(f, t, msg.as_string())
    sleep(5)
    print('from: '+str(msg['From']))  #for debuging
    print('[+] emali send from {} to {}'.format(f,t)) 
    s.quit()

here is the problematic part. its seem that all the emails are send only from the first msg[from] that I define.

output:

from: asv@acdc.co.il
[+] emali send from asv@acdc.co.il to orhalimi@mailinator.com
from: asv@acdc.co.il
[+] emali send from sss@Nisha.com to  or@mailinator.com

msg[from] doesn't get change in the next round of the loop even if f changed. but msg['To'] work without problem.

Really weird, Thanks for any help.

Edit: Show how msg is defined

I make a multipart message that attach html with option to attach file.

msg = MIMEMultipart()
if not opts.subject: msg['Subject'] = ' '
else: msg['Subject'] = opts.subject
try:
    with open(opts.html,'r') as f:
        html = f.read()
    part1 = MIMEText(html, 'html')
    msg.attach(part1)
except Exception as e:
    print('html: '+ str(e))

if(opts.file):
    try:
        with open(opts.file, 'rb') as f:
            maintype, subtype = 'application', 'octet-stream'
            part2 = MIMEBase(maintype, subtype)
            part2.set_payload(f.read())
        encoders.encode_base64(part2)
        part2.add_header('Content-Disposition', 'attachment', filename=opts.file)
        msg.attach(part2)

    except Exception as e:
        print('file: '+ str(e))

Edit2: After trying the suggesting stuff

You are right about the same behavior. when I added print('To: '+str(msg['From'])) The output got stuck on the first value. output:

from: asv@acdc.co.il
To: asv@acdc.co.il
[+] emali send from asv@acdc.co.il to orhalimi@mailinator.com
from: asv@acdc.co.il
To: asv@acdc.co.il
[+] emali send from sss@Nisha.com to  or@mailinator.com

but when I change it to replace and set them before its work. output:

from: asv@acdc.co.il
To: orhalimi@mailinator.com
[+] emali send from asv@acdc.co.il to orhalimi@mailinator.com
from: sss@Nisha.com
To:  or@mailinator.com
[+] emali send from sss@Nisha.com to  or@mailinator.com

Anyone know why? I remember list can redefine easy in python.

Its because its appending and not replacing your msg attribute value.

You can use replace_header or del .

If you use replace make sure the check of attribute exists or not.

if msg.has_key('From'):
    msg.replace_header('From', f)
else:
    msg['From'] = f

Other way is clearing the attribute, and assign value -

del msg['From']
msg['From'] = f